6_stringFormatting.py

def print_formatted(number):
    """
    Given an integer,n , print the following values for each
    integer i from 1 to n:

    1. Decimal
    2. Octal oct()
    3. Hexadecimal (capitalized) hex()
    4. Binary bin()
    The four values must be printed on a single line in the order
    specified above for each i from 1 to n. Each value should be
    space-padded to match the width of the binary value of n.

    Input Format
    A single integer denoting n.

    Constraints
    1<=n<=99

    Output Format

    Print n lines where each line (in the range 1<=i<=n) contains the
    respective decimal, octal, capitalized hexadecimal, and binary values of i.
    Each printed value must be formatted to the width of the binary value of n. 

    Sample Input
    17
    Sample Output
    1   1   1     1
    2   2   2    10
    3   3   3    11
    4   4   4   100
    5   5   5   101
    6   6   6   110
    7   7   7   111
    8   10  8  1000
    9   11  9  1001
    10  12  A  1010
    11   3  B  1011
    12  14  C  1100
    13  15  D  1101
    14  16  E  1110
    15  17  F  1111
    16  20 10 10000
    17  21 11 10001
    """
    
    if 1<=number<=99:
        width = len('{:b}'.format(number))
        for i in range(1, number+1):
            decimal = str.rjust(str(i), width)
            octal = str.rjust((oct(i)[2:]), width)
            hexadecimal = str.rjust(hex(i)[2:].upper(), width)
            binary = str.rjust((bin(i)[2:]), width)
            print(decimal, octal, hexadecimal, binary)